如何在linux下输出当前时间

如何在linux下输出当前时间

用localtime可直接分解出年月日时分秒

QUOTE:





        

            struct tm *ptm; long ts; int y,m,d,h,n,s; ts = time(NULL); ptm = localtime(&ts); y = ptm->tm_year 1900; //年 m = ptm->tm_mon 1; //月 d = ptm->tm_mday; //日 h = ptm->tm_hour; //时 n = ptm->tm_min; //分 s = ptm->tm_sec; //秒

        

   





一个有趣的例子： QUOTE:





        

            #include <stdio.h>#include <time.h>#include <unistd.h>int main() {while (1) {time_t sec = time(NULL);struct tm t = *localtime(&sec);printf("\x1b[2J"); /* clear screen and home cursor */printf("\x1b[31;40m"); /* red foreground, black background */printf("\x1b[11;29H"); /* moves cursor to line 11, column 29 */printf(" -----^--^----- \n");printf("\x1b[12;29H");printf("|\td:d:d: |\n", t.tm_hour, t.tm_min, t.tm_sec);printf("\x1b[13;29H");printf(" -------V------ \n");sleep(1);}return 0;}